Density of 6N Na2CO3 solution in water is 12g ml^-1.
The percentage by weight of Na2CO3 in solution is
(a) 53
(b) 39.15 (c) 13.25
(d) 26.5
pls answer with steps
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Answer:
Molality is the number of moles of solute dissolved in 1 kg of solvent.
Molality= mass of solvent in kg number of moles of solute
Let W g of sodium carbonate are dissolved.
The molar mass of Na2CO3=2(23)+12+3(16)=46+12+48=106 g/mol
The number of moles of Na2CO3=106 g/mol W g= 0.009434 W mol
Mass of water = 250 g= 0.250 kg
0.1 m= 0.250 kg 0.009434 W mol
W= 2.65 g
Hence, 2.65 grams of Na2CO3 should be dissolved in 250 grams of water to prepare 0.1 m solution
Explanation:
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