Question

Density of a 2.05 m solution of acetic acid in water is 1.02 g/ml .the molarity of the solution is

Answer 1

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Answer 2

Answer: 2.28 mol/kg

Explanation: Please check your question once again. Shouldn’t it be molality that is required?

Density of solution= mass of solution/volume of solution

1.02= mass of solution/1000 ml

Mass of solution= 1020 g

Molar mass of acetic acid= 60 g

Molarity= (m/M)*1/V*1000

2.05= (m/60)*(1/1000)*1000

m= 2.05*60= 123 g= mass of solute

Mass of solvent= mass of solution- mass of solute

= 1020- 123= 897 g

Molality= (m/M)*(1000/mass of solvent)

= (123/60)*(1000/897)

= 2.28 mol/kg= 2.28 m