Question

Density of a 2.05 m solution of acetic acid in water is 1.02 g/ml.1.02 g/ml. The molarity of the solution is

Answer 1

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Answer 2

Answer:

  m = 2.285mol kg⁻¹

Explanation:

molality - m

molarity - M

Density - d

M₂ - Molecular mass - CH₃COOH = 60g

m = 1000M / 1000d - MM₂

m = 1000 × 2.05 / (1000 × 1.02) - (2.05 × 60)

m = 2050 / 1020 - 123

m = 2050 / 897

m = 2.285mol kg⁻¹