Question

Density of a gas at 27 °C and 1 atm is 256 g/L. Calculate its molar mass .(R= 0.0821
atm mol-'k')

Answer 1

Answer:

5.66666

Explanation:

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Answer 2

The molar mass of the gas which is given above is equal to 63gm/mole

Explanation:

• According to the equation , pV = nRT= mRT/M , where M is the molar mass of the gas which is given , also d= m/V

• Hence M= d RT/P ,

Given,

1. the temperature of the gas is 27 degree Celsius or 300 Kelvin
2. The pressure is 1 atmospheric pressure
3. The density is 256 gram per litre or 0.256 g per cc

Hence M =0. 256 x300x0.0821/10⁶ = 63 gm/mole

• hence the molecular weight of the gas which is given is equal to 63 gram per mole provided it is an ideal gas

To know more,

An ideal gas has a volume of 15ml, a temperature of 20C and a .

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