Question

Density of a gas at 300 k and 210 torr is 0.34 g/l. What is its molar mass?

Answer 1

Solution is in the attachment. Mark as brainliest!

Answer 2

Answer: 29.9 g/mol

Explanation:

To calculate the molar mass of gas, we use the equation given by ideal gas equation:

$PV=nRT$

Number of moles (n) can be written as: $n=\frac{m}{M}$

where, m = given mass

M = molar mass

$PV=\frac{m}{M}RT\\\\PM=\frac{m}{V}RT$

where,

$\frac{m}{V}=d$ which is known as density of the gas

The relation becomes:

$PM=dRT$    .....(1)

We are given:

d = Density of gas = 0.34 g/L

R = Gas constant = $0.08206\text{ L atm }mol^{-1}K^{-1}$

T = temperature of the gas = 300 K

P = pressure of the gas = 210 torr = 0.28 atm    (760 torr = 1 atm)

M = molar mass of gas = ?

Putting values in equation 1, we get:

$0.28atm\times M=0.34g/L\times 0.08206\text{ L atm }mol^{-1}K^{-1}\times 300K$

$M=29.9g/mol$

Thus molar mass of the gas is 29.9 g/mol.