Question

Density of a gas is found to be 5.46 g/dm3 at 27 °C at 2 bar pressure. What will be its density at STP?​

Answer 1

Answer:

3.0g dm-³

Explanation:

P=n/v RT= m/v×RT/M =dRT/M

or d=PM/RT or d alpha R/T

d1/d2=P1/P2×T1/T2

or d2=d1×P2×T1/P1×T2

d2=5.46×1×300/2×273

=3.0g dm-³

Answer 2

Density of a gas is found to be 5.46 g/dm3 at 27 °C at 2 bar pressure. What will be its density at STP?

P1 = 1.013 bar

S1 = ?

T1 = 273.15 k

P2 = 2 bar

S2 = 5.46 g/ cc

T2 = 27 + 273 . 15 = 300.15 k

_______________________________

$\frac{P1}{S1T1} = \frac{P2}{S2T2}$

_____________________________

S.T.P = Standard temperature and pressure (STP) .

Some formula important to remember :-

1. PV = nRT ( P stands for pressure, V stands for volume, T stands for temperature , R means constant .
2. __ K − 273.15 = ___C ( To change Kelvin into temperature )