Question

Density of a mixture of CO and CO2 at 303K and 73 cm of Hg is 1.5 g L^-1.what is the mole percent of two gases in the mixture?
Pls explain nicely

Answer 1

Answer:

Explanation:

PV =wRT/M

OR P=wRT/M*T

OR P=dRT/M

P=73/76 atm, d=1.5g/litre ,M=?

T=303K, R=0.0821 L atm  k power -1 mol power -1

therefore 73/76=1.5*0.082*303/M

M = 38.85 (molecular mass of the mixture)

Suppose, Total moles = 100

MOLES of CO = a,

Moles of CO2 100 – a

Mass of CO2 = (100 – a)44

Total mass = 28a + (100 – a) 44

Molecular mass of mixture = 28a (100 – a)44/100

But molecular mass of mixture is 38.85

38.85 = 28a + (100 - a)44/100

a = 32.19

Mole percent of CO = 31.19

Mole percent of CO2 = 67.81

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