Question

Density of a solution containing 13%by mass of sulfuric acid is 1.09g/ml. Calculate molarity.

Answer 1

Answer:

Volume of 100 g of the solution

=

d

100

=

1.09

100

mL

=

1.09×1000

100

litre

=

1.09×10

1

litre

Number of moles of H

2

SO

4

in 100 g of the solution =

98

13

Molarity =

Volume of soln. in litre

No. of moles of H

2

SO

4

=

98

13

×

1

1.09×10

=1.445M

We know that,

Normality = Molarity ×n

=1.445×2 [n=

Eq.mass

Mol.mass

=

49

98

=2]

=2.89N

Hence, the molarity of the given solution is 1.445 M and normality is 2.89 N

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