Question

Density of a solution containing 13% by mass of sulphuric acid is 0.98 g/mL. Then molarity of solution will be. ​

Answer 1

Answer: 1.44 M

Explanation: Density= 1.09

1.09= mass of solution/volume of solution

When density is 1.09, there is 109 g of solution in 100 ml of solution or 1090 g in 1000 ml of solution.

Mass of solution= 1090 g

Mass of H2SO4= 13% of 1090 g

= (13/100)*1090

= 1417/10

= 141.7 g

Molar mass of H2SO4= 98 g

Molarity= (m/M)*(1/V)*1000

= (141.1/98)*(1/1000)*1000

= 1.44 M