Question

Density of a solution containing 14% by mass of
sulphuric acid is 1.05 gm/mL. What is the molarity
of solution?
(A) 0.5 M
(B) 1.0M
(C) 1.5 M .
(D) 2.0M​

Answer 1

Let the mass of the solution be 100 gm.

mass of sulphuric acid in solution = 14 gm.

Density of the solution = 1.05 g/mL.

∴ Volume of solution = mass of solution/density

∴ Volume of solution = 100/1.05

∴ Volume of solution = 95.24 mL.

Moles of Sulphuric acid = Mass of acid/Molecular mass.

∴ Moles = 14/98

∴ Moles = 0.143 moles.

Now, using the formula of molarity,

Molarity = (No of moles of solute/Volume of sol in ml.) × 1000

∴ Molarity = 0.143/95.24 × 1000

∴ Molarity = 1.499 M.

Hence, the molarity of the solution is 1.499 M.

hope it is useful