Question

Density of a Substance is p-m/v
Where M-(20 +0.2) Kg and
v=( 10+0.1) m3 calculate the
percentage
error in P.
​

Answer 1

Answer:

Percentage error in density is 2%

Explanation:

As we know that

\rho = \frac{M}{V}ρ=VM

now we have

ln(\rho) = \ln(M) - ln(V)ln(ρ)=ln(M)−ln(V)

now we have

\frac{d\rho}{\rho} =\pm \frac{dM}{M} \pm \frac{dV}{V}ρdρ=±MdM±VdV

so we have

M = 20 \pm 0.2M=20±0.2

V = 10 \pm 0.1V=10±0.1

so we have

\frac{d\rho}{\rho} =\pm \frac{0.2}{20} \pm \frac{0.1}{10}ρdρ=±200.2±100.1

\frac{d\rho}{\rho} = \pm 0.01 \pm 0.01ρdρ=±0.01±0.01

\frac{d\rho}{\rho} \times 100 = 2ρdρ×100=2 %

Explanation:

please mark me as brainlist