Question

density of dry air containing N2 and O2 is 1.46 g/L at 740 mm Hg and 300 K . what is the % composition of N2 by mass in air.​

Answer 1

Correct option is

c,.)70.02%

Answer 2

Answer:

We know that PV=nRT

Since, 1 atm= 760 mm of Hg

∴ 740 mm of Hg = 0.97 atm

M= dRT/P

= 1.15×0.082×300/0.97

=29.16 g mol −1

Let M1 be mass fraction of N2

M2be that of O2 M2=(1−M1)

M1×28+M2×32=29.16

On solving 4W1=2.83

W 1=0.7008

So percentage of Nitrogen is 70.08%

Explanation:

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