Question

Density of iron is 7.8 g/cc and induced magnetic
field in iron is 1 tesla then find magnetic dipole
moment of each iron atom,
(1) 57 x 10-21 Am? (2) 9.5 x 10 24 Ama
(3) 21 x 10-24 Am? (4) 37 x 10-24 Arn?​

Answer 1

Answer:

Magnetic moment per iron atom is given as

$\frac{M}{N} = 9.5 \times 10^{-24} Am$

Explanation:

As we know that magnetization is defined as net magnetic moment per unit volume

so it is given as

$I = \frac{B_i}{\mu_o}$

so we have

$I = \frac{1}{4\pi \times 10^{-7}}$

$I = 7.96 \times 10^5$

now we have

total magnetic moment = (magnetization)(Volume)

$\frac{M}{N} = (7.96 \times 10^5)(V)$

$\frac{M}{N} = \frac{(7.96 \times 10^5)(55.85 \times 1.66 \times 10^{-27})}{7800}$

$\frac{M}{N} = 9.5 \times 10^{-24} Am$

#learn

Topic : Magnetization

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