Question

Density of NaCl is 2.165 g/cm³. Calculate the number of atoms in 1.0 cm³ of NaCl at 25° C?​ Please help

Answer 1

your answer:

1 cm³ of NaCl weighs 2.165 g

Molar mass of NaCl = 58.5

No. of moles of NaCl in 2.165 g is: $\frac{2.165}{58.5}$ = 0.037 moles

one mole of NaCl has 6.022 x 10²³ atoms

The, 0.037 moles of NaCl will have: 0.037 x 6.022 x 10²³ = 0.222814 x 10²³ molecules = 2.22814 x 10²² molecules

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Answer 2

Answer:

this is your answer hope it helps you