Density of rubber is d.A thick rubber cord of length L and cross section area A undergoes elongation under its own weight on suspending it. This elongation is proportional to
Answers
Answered by
0
Elongation is directly proportional to dL²
Given-
- Density of rubber = d
- Length of rubber cord = L
- Cross section area of rubber cord = A
A thin section dx is taken in the rod.
mg is the force acting in the thin section dx in downward direction.
Suppose elongation in the thin section is dy.
We know that Young's modulus (Y) is = mg/A/dy/dx
Y = mg × dx / A × dy
dy = mg × dx / A × Y
By putting the value of mg and integrating it we get
We know that mass is equals to volume × density
m = x A d
dy = x A d dx / AY
∫dy = d/Y ∫x. dx ( limits of dy is from 0 to X and limits of dx is from 0 to L)
X = d/Y (L²/2)
X = dL²/2Y
X is the elongation
Answered by
0
Answer:
Increment in length l=2YdL2g
∴l ∝ dL2
Similar questions