Physics, asked by gowthem9182, 6 months ago

Density of silver 10.5g/cm3 calculate the length in cubic piece of silver with mass 0.443kg

Answers

Answered by Makkii
0

Convert kilograms to grams:

0.443 \: kg \times  \frac{1000 \: g}{1 \: kg}  = 443 \: g

Then divide the density to the mass to get the volume:

\frac{443 \: g}{ \frac{10.5 \: g}{ {cm}^{3} } }  = 443 \: g \times \frac{ {cm}^{3} }{10.5 \: g}  = 42.19 \:  {cm}^{3}

Lastly, get the cube root of it to find the sides:

 {s}^{3}  = v \\  \sqrt[3]{ {s}^{3} }  =  \sqrt[3]{42.19  \: {cm}^{3} }  \\ s = 3.48 \: cm

The answer is 3.48 cm

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