Question

density of water is 1gper ml the concentration of water in mol per litre is​

Answer 1

Answer:

55.555 mol per litre.

Explanation:

Given density of water is 1 g/mL.

This means one mL of water weighs 1 gram.

Therefore 1 L (1000 mL) weighs 1000 g of water.

Let us calculate number of moles(n) of water present in 1 L (GMW of water is 18g),

n = 1000/18  (since number of moles = weight/GMW).

n = 55.555 moles.

i.e 1 L contains 55.555 moles.

The definition of molarity states that, "Number of moles of substance present in 1 L of a solution".

Here water contains 55.555 moles per litre.

Therefore the concentration of water is 55.555 mol per litre.

Answer 2

Answer:

Given:

Density of water is (d) =  $\sf 1 \; g/ml$

To Find:

concentration of water in mole per litre

Solution:

We know that

Molarity (M) is defined as the number of moles of the solute per litre of solution.

The formula to calculate Molarity is

$\boxed{\sf M = \dfrac{No\;of \;moles\;of\;solute}{Volume\; of\; solution(in \;litres)} }$

Given that,

Density of water = $\sf 1 \; g/ml$

Hence,

Mass of 1 L of water will be

$\boxed{\sf Mass=Density \times Volume}$

$\sf \implies 1\dfrac{Kg}{L} \times 1L$

$\implies \sf Mass = 1\;Kg$

$\sf \implies Mass=1000\;g$

We are asked to find the the concentration of water in mole per litre

We know that,

Mole (n) is the amount of substance present.

The formula to calculate Mole is

$\boxed{\sf Mole=\dfrac{Mass}{Molar\;mass}}$

Mathematically,

$\boxed{\sf n=\dfrac{m}{M} }$

Hence,

The number of moles in 1 Kg of Water (H₂O)

We know that Molar mass of water is 18

∵ (2 + 16) = 18

Therefore,

$\implies \sf n = \dfrac{1000}{18}$

$\sf \implies n=55.55$

$\boxed{\sf n=55.55}$

So Molarity (M) is the Concentration per litre

$\implies \sf M = \dfrac{55.5}{L}$

The concentration of water is

55.5 mole per litre