Question

dentify oxidising agent and reducing agent from following reactions:

(a) H2 (g) + Cl2 (g) → 2HCl (g)

(b) 2Al (s) + Cr2O3 (s) → Al2O3 (s) + 2Cr (​

Answer 1

Answer:

The Oxidation number of Sulphur changes from −2 to 0 . So Sulphur is oxidised.

The Oxidation number of Chlorine changes from 0 to −1. So Chlorine is reduced

hope it helps you

Answer 2

Explanation:

H2 is oxidized (addition of cl2; non metal)

therefore it is the reducing agent

and cl2 is being reduced by addition of H2 therefore it is the oxidizing agent.

Al is being oxidised therefore it is the reducing agent

Cr2O3 is being reduced due to removal of 0 therefore it is oxidising agent.