Question

Depak's age is three times of his son's age. Ten years ago he was five times his son's age. find their present ages.​

Answer 1

Step-by-step explanation:

Let the present age of son be x years.

Then, the age of his father Aman will be 3x.

So, 10 years ago, their ages will be (x−10) years and (3x−10) years respectively.

According to the given condition, we have

3x−10=5(x−10)

⇒3x−10=5x−50

⇒5x−3x=−10+50

⇒2x=40⇒x=20

∴ Son's age =20 years and Aman's age =20×3=60 years.

Answer 2

Answer:

60 years is Deepak's Age

Step-by-step explanation:

Let Deepak's son's age be = x

then, Deepak's age is = 3x

10 years ago,

His son's age = x - 10

Deepak's age = 5(x-10)

Then ATQ,

$3x - 10 = 5(x - 10) \\ = > 3x - 10 = 5x - 50 \\ = > - 2x = - 40 \: \: \: \: \: \: \: \: \: \: \: \: \\ = > 2x = 40 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ = > x = 20 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

Deepak's Age = 3x => 3 × 20 => 60 years

Deepak's age is 60 years now & his Son's age is 20 years now.

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