Question

depauls mother is 4 years more than three times as old as Deepa is now six years from now she will be 8 years more than twice as old as Deepa will be then how old is each of them now​

Answer 1

Step-by-step explanation:

let deepa's age=x

her mother age y=4+3x

after 6 years,

mother age=y+6=8+2(x+6)

so 8+2x+12=y+6

so 20+2x=y+6

so 14+2x=y

equate both of them

4+3x=14+2x

x=10

so mother is 34