Environmental Sciences, asked by himansu3382, 1 year ago

Dependence of intensity of gravitational field (e) of earth with distance (r) from centre of earth is correctly represented by

Answers

Answered by QGP
50
The graph is attached.


Intensity of gravitational field is also known as gravitational acceleration \textbf{\textit{g}}.

Now, Let

Earth's Radius = R
Earth's Mass = M
Universal Gravitational Constant = G

Also, r = Distance from center of Earth


 Now, the value of g is given by the following formulas. Their graph description is also given.



\boxed{g = -\frac{GMr}{R^3} \, \, \, for \, \, r \ \textless \ R} \, \, \, \implies \text{Straight Line} \\ \\ \\ \boxed{g = -\frac{GM}{R^2} \, \, \, for \, \, r=R } \, \, \, \implies \text{Constant Value} \\ \\ \\ \boxed{g = -\frac{GM}{r^2} \, \, \, for \, \, r\ \textgreater \ R} \, \, \, \implies \text{Hyperbola}

As we can see, 

For r<R, the value of g is directly proportional to R. So the graph is a straight line. 

g reaches a Maximum Value for  r = R



For r > R, the value of g is inversely proportional to r^2. So the graph is a decreasing hyperbola.

The graph is attached as an image.

Attachments:
Answered by shreya2412
13

Answer: gravitational field intensity is -ve

Explanation:

Attachments:
Similar questions