deride expression for elastic potential energy of all stetched wire
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Hooke's Law, F = -kx, where F is the force and x is the elongation.
The work done = energy stored in stretched string =F.dx
The energy stored can be found from integrating by substituting for force,
and we find,
The energy stored = kx2/2, where x is the final elongation.
The energy density = energy/volume
= (kx2/2)/(AL)
=1/2(kx/A)(x/L) = 1/2(F/A)(x/L) = 1/2(stress)(strain)
Regards,
swarna
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The work done = energy stored in stretched string =F.dx
The energy stored can be found from integrating by substituting for force,
and we find,
The energy stored = kx2/2, where x is the final elongation.
The energy density = energy/volume
= (kx2/2)/(AL)
=1/2(kx/A)(x/L) = 1/2(F/A)(x/L) = 1/2(stress)(strain)
Regards,
swarna
hope this will help u plz follow me and Mark it as brainliest plz plz plz
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