Question

derieve the equation work done =mv2/2 (kinetic energy)​

Answer 1

if an object of mass m acquires a velocity v after traveling a distance S form rest then,

we have V2=u2+2as

v2=0+2as

v2=2(F/M)s

F. s= 1/2 mv2

w=1/2mv2

due to this work the object acquires the capacity of doing work.

since, it's kinetic energy K=1/2mv2

Answer 2

Answer:

HELLO YOUR ANSWER IS GIVEN BELOW...

LET W = WORK DONE

F = FORCE

S = DISPLACEMENT

m= MASS

a = ACCELERATION

V = FINAL VELOCITY

U = INITIAL VELOCITY

THEN,

W = F× S

= m ×a × s ( since... F= ma)

AND WE KNOW THAT

V^2 - U^2 = 2 a s

OR (V^2 - U^2 ) /2 = a× s

PUTTING THIS EQN. IN THE ABOVE ..

WE GET..

W = m × (V^2 - U^2) /2

= (m V^2) /2 - (mU^2) /2

IF THE INTIAL VELOCITY IS 0 i.e U= 0

THEN WE CAN WRITE AS ...

W = mV^2 /2

HENCE PROVED.