Question

derif an expresion for value of g on surface of the earth

Answer 1

ʜᴇy ᴜꜱᴇʀ

ʜᴇʀᴇ ɪꜱ yᴏᴜʀ ᴀɴꜱᴡᴇʀ :-

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ᴍᴀꜱꜱ ᴏꜰ ᴇᴀʀᴛʜ = 6 × 10^24

ɢʀᴀᴠɪᴛᴀᴛɪᴏɴᴀʟ ᴄᴏɴꜱᴛᴀɴᴛ = 6.67 × 10^-11

ʀᴀᴅɪᴜꜱ ᴏꜰ ᴛʜᴇ ᴇᴀʀᴛʜ = 6.4 × 10^6

ʙy ɴᴇᴡᴛᴏɴꜱ ᴜɴɪᴠᴇʀꜱᴀʟ ʟᴀᴡ ᴏꜰ ɢʀᴀᴠɪᴛᴀᴛɪᴏɴ

$f = \frac{gmm}{ {r}^{2} } \\ \\ f = mg \\ \\ g = \frac{gm}{ {r}^{2} } \\ \\ = \frac{6.67 \times {10}^{ - 11} \times 6 \times {10}^{24} }{ {(6.4 \times {10}^{6} )}^{2} } \\ \\ = 9.77 \: m {s}^{ - 2}$

Answer 2

In the first equation above, g is referred to as the acceleration ofgravity. Its value is 9.8 m/s2 onEarth. That is to say, the acceleration of gravity on thesurface of the earth at sea level is 9.8 m/s2. ... There are slight variations in the value of g aboutearth's surface.