derivation f=ma with statement
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According to Newton's Second law:
Force applied = change in momentum
=> F = dp/dt ...............(a)
And, we know that:
momentum = mass×velocity
=> p = mv
Differentiate the above equation:
=> dp = m.dv
Put [dp = m.dv] in (a)
That is, F = dp/dt
= (m.dv)/dt
= m.(dv/dt)
but dv/dt = acceleration = a.
Hence, F = m×a
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