Question

derivation for adaibatic condition (class 11th ) physics?.​

Answer 1

Explanation:

am in class 10 sorry I can't have any solution

Answer 2

Heyy Mate Here Is ur Answer...

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.The adiabatic process can be derived from the first law of thermodynamics relating to the change in internal energy dU to the work dW done by the system and the heat dQ added to it.

dU=dQ-dW

dQ=0 by definition

Therefore, 0=dQ=dU+dW

The word done dW for the change in volume V by dV is given as PdV.

The first term is specific heat which is defined as the heat added per unit temperature change per mole of a substance. The heat that is added increases the internal energy U such that it justifies the definition of specific heat at constant volume is given as:

Cv=dUdT1n

Where,

n: number of moles

Therefore, 0=nCvdT+PdV (eq.1)

From the ideal gas law, we have

nRT=PV (eq.2)

Therefore, nRdT=PdV+VdP (eq.3)

By combining the equation 1. and equation 2, we get

−PdV=nCvdT=CvR(PdV+VdP) 0=(1+CvR)PdV+CvRVdP 0=R+CvCv(dVV)+dPP

When the heat is added at constant pressure Cp, we have

Cp=Cv+R 0=γ(dVV)+dPP

Where the specific heat ɣ is given as:

γ≡CpCv

From calculus we have, d(lnx)=dxx 0=γd(lnV)+d(lnP) 0=d(γlnV+lnP)=d(lnPVγ) PVγ=constant

Hence, the equation is true for an adiabatic process in an ideal gas.

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