derivation of angular acceleration
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φ = φ₀+ω₀*t + ε*t²/2
φ ' = ω = ω₀ + ε*t
ε = (ω - ω₀) / t
φ ' = ω = ω₀ + ε*t
ε = (ω - ω₀) / t
swastikrnaik735:
I didn't understand
Can you please explain it in easy words
please
We must take the first derivative of the angle, and from the obtained expression to Express the angular acceleration of Epsilon.
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