Question

Derivation of centripital ?​

Answer 1

From the diagram given above, we can say that,

PQ +QS=PS

-v1+v2=∆v

∆v=-v1+v2

Derivation Of Centripetal Acceleration

∆v/AB=v/r

AB= arc AB =v∆t

∆v/u∆v=u/r

∆v/∆t= v2/r

a=v2/r

The triangle PQS and AOB are similar. Therefore,

Derivation Of Centripetal Acceleration