derivation of de broglie relatiship ??
Answers
Answered by
1
According to Einstein
E=mc^2
for a matter of mass m moving with velocity v
E= mv^2
According to plank
E=hf (where f is the frequency)
So mv^2 = hf
mv^2= hv/z (where z is the wavelenght)
mv=h/z
z=h/mv
According to de Broglie , whenever a matter of mass m, is allowed to move with velocity v, it propagates like a wave
Hope it helps.... :-)
E=mc^2
for a matter of mass m moving with velocity v
E= mv^2
According to plank
E=hf (where f is the frequency)
So mv^2 = hf
mv^2= hv/z (where z is the wavelenght)
mv=h/z
z=h/mv
According to de Broglie , whenever a matter of mass m, is allowed to move with velocity v, it propagates like a wave
Hope it helps.... :-)
Answered by
0
Answer:
Explanation:
De Broglie hypothesis says that all matter has both particle and wave nature. The wave nature of a particle is quantified by de Broglie wavelength defined as where is the momentum of the particle. ... Historically, de Broglie hypothesis was the next step in quantum theory after Planck, Einstein and Bohr.
Similar questions
CBSE BOARD XII,
8 months ago
Science,
8 months ago
Chemistry,
8 months ago
Math,
1 year ago
Math,
1 year ago