Derivation of De - Broglie wave equation........???
Please don't spam......
❤❤❤❤
Answers
Answered by
7
Hola User______________
Here is Your Answer...!!!!
_______________________
⭐Actually welcome to the concept of the MODERN PHYSICS / ATOMIC STRUCTURE. .⭐〽
⭐Basically this is the concept of the
⭐EINSTEIN'S EQUATION OF ENERGY AND THE PLANKS QUANTUM THEORY
⭐we know that energy is given by
⭐E = mc^2 according to the theory of relativity
⭐Also by the Quantum theory we know that
⭐E = hv ,since here V = frequency and we know that ( v = c/lambda )
⭐so now equating both we get as
⭐hc/ lambda = mc^2
⭐now cancelling velocity from both side and rearranging in terms of wave length (lambda ) we get as
⭐-\ ( lambda) = h ÷ mc
⭐since we know that momentum (p) = mv
⭐so replacing we get as the DE - broglies wavelength.
⭐lambda = h/ p
________________________
Hope it helps u....☺
Here is Your Answer...!!!!
_______________________
⭐Actually welcome to the concept of the MODERN PHYSICS / ATOMIC STRUCTURE. .⭐〽
⭐Basically this is the concept of the
⭐EINSTEIN'S EQUATION OF ENERGY AND THE PLANKS QUANTUM THEORY
⭐we know that energy is given by
⭐E = mc^2 according to the theory of relativity
⭐Also by the Quantum theory we know that
⭐E = hv ,since here V = frequency and we know that ( v = c/lambda )
⭐so now equating both we get as
⭐hc/ lambda = mc^2
⭐now cancelling velocity from both side and rearranging in terms of wave length (lambda ) we get as
⭐-\ ( lambda) = h ÷ mc
⭐since we know that momentum (p) = mv
⭐so replacing we get as the DE - broglies wavelength.
⭐lambda = h/ p
________________________
Hope it helps u....☺
Similar questions