Question

derivation of formula a³-b³

Answer 1

Hey! Here it is::-

▶▶a³-b³=(a+b)(a²-ab+b²)

Answer 2

Step-by-step explanation:

a³-b³=a³-b³+a²b-a²b+b²a-b²a

=a³-a²b -b³+ab²+a²b-b²a

=a²(a-b)+b²(a-b)+ab(a-b)

=(a-b)(a²+b²+ab)

a²+b²+2ab=(a+b)²

a²+b²-2ab=(a-b)²

a²-b²=(a+b)(a-b)

a³+b³=(a+b)(a²+b²-ab)

a³-b³=(a-b)(a²+b²+ab)

a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ca)

a³+b³+3ab(a+b)=(a+b)³

a³-b³-3ab(a-b)=(a-b)³