derivation of heat formula
( Q = m. S. ∆T )
Answers
Answer:
Specific Heat formula is articulated as
C=ΔQ/mΔT
Where,
Δ Q is the heat gained or lost,
Δ T is the temperature difference.
The temperature difference is given by Δ T = (Tf – Ti), where the final temperature is Tf and the initial temperature is Ti .
Specific Heat formula is made use of to find the specific heat of any given material, its mass, heat gained or temperature difference if some of the variables are given. It is articulated in Joule/Kg Kelvin (J/Kg K).
Specific Heat Solved Examples
Underneath are some questions based on specific heat which will be useful for you.
Problem 1: Calculate the heat required to raise 0.6 Kg of sand from 30oC to 90oC? (Specific Heat of sand = 830 J/KgoC)
Answer:
Known:
Mass of sand m = 0.6 Kg,
Δ T (Temperature difference) = 90oC – 30oC = 60oC
C (Specific Heat of sand) = 830 J/KgoC
The specific heat is given by, C=ΔQmΔT
Henceforth, Heat required is given by Q = C m Δ T
= 830 J/KgoC × 0.6 Kg × 60oC
= 29880 J.
Problem 2: Compute the temperature difference if 50 Kg of water absorbs 500 K J of heat?
Answer:
Known:
m (Mass) = 50 Kg,
Q (Heat transfer) = 500 KJ,
C (Specific Heat of water) = 4.2 × 103 J/KgoC
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