DERIVATION OF HERONS FORMULA??? PLZZ ANYONE EXPLAIN ME ..STEP BY STEP
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See diagram. Apply Pythagoras theorem.
let s = (a+b+c)/2
c² = h² + x² ---(1)
b² = h² + (a-x)²
= h² + a² - 2ax + x²
= h² + a² - 2 a x + c² - h²
x = (a² + c² - b²) / 2a
Substitute value of x in (1) h² = c² - (a² + c² - b²)²/4a²
h² = [ (2ac)² - (a² + c² - b²)² ] / 4a²
= [ (2ac +a² + c² - b²) (2ac - a² - c² + b²) ] /4a²
= [ (a + c + b)(a+c - b) ( b - a + c) ( b + a - c) ] / 4 a²
= [ (2 s) (2s - 2b) (2s - 2a) (2s - 2c)]/4a²
Area of ΔABC = 1/2 * a * h = √[s(s-a)(s-b)(s-c)
proved.
let s = (a+b+c)/2
c² = h² + x² ---(1)
b² = h² + (a-x)²
= h² + a² - 2ax + x²
= h² + a² - 2 a x + c² - h²
x = (a² + c² - b²) / 2a
Substitute value of x in (1) h² = c² - (a² + c² - b²)²/4a²
h² = [ (2ac)² - (a² + c² - b²)² ] / 4a²
= [ (2ac +a² + c² - b²) (2ac - a² - c² + b²) ] /4a²
= [ (a + c + b)(a+c - b) ( b - a + c) ( b + a - c) ] / 4 a²
= [ (2 s) (2s - 2b) (2s - 2a) (2s - 2c)]/4a²
Area of ΔABC = 1/2 * a * h = √[s(s-a)(s-b)(s-c)
proved.
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