Question

derivation of kinetic energy​

Answer 1

$\mathfrak{Derivation \: of \:Kinetic \: Energy}$

$\mathsf{Things \: to \: know \: before\: Derivation}$

$\mathsf{\implies Work done = Fs}$

$\mathsf{\implies v² = u² + 2as}$

$\mathsf{\implies s = \frac{v² - u²}{2a}}$

$\mathsf{\implies u = 0 m/s \: for \:a \: body \: starting \: from \: rest}$

$\mathsf{\implies Work \: Done = \: Energy}$

$\mathsf{\implies Kinetic \: Energy \: is \: also \: written \: as \: E_k}$

$\mathsf{\implies Force = mass \: × \: acceleration \: = ma}$

$\mathsf{Derivation}$

$\mathsf{\hookrightarrow E_k = Work done = Fs }$

$\mathsf{\hookrightarrow \: = \: Fs \: = ma × s }$

$\mathsf{\hookrightarrow E_k = m × \frac{v² - u²}{2a} × s}$

$\mathsf{\hookrightarrow E_k = \frac{1}{2}mv²}$

Answer 2

The energy produced by a body due to the virtue of its motion is called kinetic energy.

${ \red{ \bf{ Derivation \: of\: kinetic \:energy:- }}}$

Let,

m=mass of a body at rest

F=force applied on the body

s=displacement in the direction of force

v=final velocity of the body

As, v²=u²+2as

v²=0²+2as

v²=2as

s=v²/2a

Then,

Work=fs

W=F×S

W=ma×v²/2a

W= mv²/

K = 1/2mv²