derivation of kinetic energy?
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Answered by
4
v² - u² = 2as
v² - 0 = 2as
a = v²/2s
WD= mas = m * v²/2s * s = mv²/2
Or, 1/2mv²
v² - 0 = 2as
a = v²/2s
WD= mas = m * v²/2s * s = mv²/2
Or, 1/2mv²
Meww:
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Answered by
3
Consider an object having mass 'm' moving with a velocity 'u'.By the application of a force 'F',it displaced through a distance 's'.Let it's velocity change from 'u' to 'v'.Let 'a' be the accileration produced.According to the equation of motion,
v^2-u^2=2as OR
s=v^2-u^2/2a...................................................................eqa=1
Force,F=ma.....................................................................eqa=2
Work done by the force,
W=Fs...............................................................................eqa=3
Use equations 1 and 2 in equation 3.
ie; W=ma*(v^2-u^2/2a)
=1/2ma(v^2-u^2)
If the object is starting from rest ,
ie; when u=0,then W=1/2mv^2
This work done is equal to the change in kinetic energy of an object.
Therefore,kinetic energy possessed by the object is
E(k)=1/2mv^2
v^2-u^2=2as OR
s=v^2-u^2/2a...................................................................eqa=1
Force,F=ma.....................................................................eqa=2
Work done by the force,
W=Fs...............................................................................eqa=3
Use equations 1 and 2 in equation 3.
ie; W=ma*(v^2-u^2/2a)
=1/2ma(v^2-u^2)
If the object is starting from rest ,
ie; when u=0,then W=1/2mv^2
This work done is equal to the change in kinetic energy of an object.
Therefore,kinetic energy possessed by the object is
E(k)=1/2mv^2
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Best answer dear....! Better than Meww's answer ^_^
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