derivation of kinetic energy?
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Answered by
3
The relation connecting the initial velocity (u) and final velocity (v) of an object moving with a uniform acceleration a, and the displacement, S is
v2 - u2 = 2aS
This gives
S =
v
2
-
u
2
/2a
We know F = ma. Thus using above equations, we can write the workdone by the force, F as
W = ma
v
2
-
u
2
/2a
or
W =
1
/2
m(
v
2
-
u
2
)
If object is starting from its stationary position, that is, u = 0, then
W =
1
2
m
v
2
It is clear that the work done is equal to the change in the kinetic energy of an object.
If u = 0, the work done will be
W =
1
2
m
v
2
.
Thus, the kinetic energy possessed by an object of mass, m and moving with a uniform velocity, v is Ek = ½ mv2
Anonymous:
Brainliest and plss
Answered by
17
Consider an object of mass, m moving with a uniform velocity, u. Let it nowbe displaced through a distance s when a constant force, F acts on it in the direction of its displacement
the work done, W is F s.W = F.S = ma sThe work done on the object will cause a change in its velocity.Let its velocity change from u to v.Let a be the acceleration produced.
v²-u²=2as
s=v²-u²/2a
F =ma
W = ma× v²-u²/2a
W = mv²-u²/2a
u = 0 (as the object starts at rest)
Ek = 1/2 mv²
the work done, W is F s.W = F.S = ma sThe work done on the object will cause a change in its velocity.Let its velocity change from u to v.Let a be the acceleration produced.
v²-u²=2as
s=v²-u²/2a
F =ma
W = ma× v²-u²/2a
W = mv²-u²/2a
u = 0 (as the object starts at rest)
Ek = 1/2 mv²
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