Derivation of Lens Formula?
Answers
Explanation:
Derivation of Lens Formula Consider a convex lens with an optical center O. Let F be the principle focus and f be the focal length. An object AB is held perpendicular to the principal axis at a distance beyond the focal length of the lens. A real, inverted magnified image A'B' is formed
Answer:
The figure above shows that the formation of a real, inverted and diminished image AB of the object AB placed beyond the centre of curvature at a distance u from the convex lens. Let v be the image distance,
According to Cartesian sign convention
Object distance (OB)=−u
Image distance (OB)=+v
Focal length (OF1=OF2)=+f
From the geometry of the figure above, right angled △ ABO and △ ABO are similar.
∴A′B′AB=O′B′OB=−v ........ (i)
Similarly, from the geometry of the figure above, right angled △ODF2 and △BAF2 are similar.
∴A′B′OD=F2B2OF2
∴A′B′AB=F2B2OF2 ( ∵ OD = AB, are the opposite sides of □ ABOD )
∴A′B′AB=OB′−OF2OF2
∴
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