derivation of lens formula with diagram
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3
Heyaa folk,
✪ Derivation of Lens Formula ✪
Let AB represent an object placed at right angles to the principal axis at a distance greater than the focal length f of the convex lens.
The image A1B1 is formed between O and F1 on the same side as the object is kept and the image is erect and virtual.
[I'm really sorry, I'm unable to attach a figure.]
Hope it helps u :)
- no4 ✯ Brainly Star ✯
✪ Derivation of Lens Formula ✪
Let AB represent an object placed at right angles to the principal axis at a distance greater than the focal length f of the convex lens.
The image A1B1 is formed between O and F1 on the same side as the object is kept and the image is erect and virtual.
[I'm really sorry, I'm unable to attach a figure.]
Hope it helps u :)
- no4 ✯ Brainly Star ✯
Answered by
4
We know that for a lens
m=v/u
and 1/v - 1/u = 1/f
1/u = 1/v - 1/f
Substituing this value in 1st equation
m = v(1/v-1/f)
m =1 - v / f
This eqn is similar to y = (slope)x + c
y=m
c=1
slope= -1/f
Hence the graph would be a straight line...
and to find the focal length from this graph we need to find the slope of the line...
As slope = 1/f
I hope u got it!
Thumbs up Plz
m=v/u
and 1/v - 1/u = 1/f
1/u = 1/v - 1/f
Substituing this value in 1st equation
m = v(1/v-1/f)
m =1 - v / f
This eqn is similar to y = (slope)x + c
y=m
c=1
slope= -1/f
Hence the graph would be a straight line...
and to find the focal length from this graph we need to find the slope of the line...
As slope = 1/f
I hope u got it!
Thumbs up Plz
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