Physics, asked by si143, 1 year ago

derivation of magnitude of centripetal force

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Answered by Ativle31
1
Hope so it helps
Centripetal force
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si143: i have the same book that you have
si143: so i can see from that
si143: but i want the complete derivation
si143: thanks for your help
Answered by TheRose
4
A body that moves in a circular motion (of radius r) at constant speed (v) is always being accelerated.  The acceleration is at right angles to the direction of motion (towards the center of the circle) and of magnitude v2 / r.

The direction of acceleration is deduced by symmetry arguments.  If the acceleration pointed out of the plane of the circle, then the body would leave the plane of the circle; it doesn't, so it isn't.  If the acceleration pointed in any direction other than perpendicular (left or right) then the body would speed up or slow down.  It doesn't. 

Now for the magnitude.  Consider the distance traveled by the body over a small time increment

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