derivation of mathematical formula for open organ pipe.
plz help me it's urgent!
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If l be the length of the tube,the wavelength of the wave is
L=lambda1/2 or lambda 1=2L.
Its called as the fundamental node.
It has 2 and 3 anti nodes so,
lambda2= L.
The frequency
f2=v/lambda2=v/L=2×v/2L=2f1.
The frequency,
f3=v/lambda3=3v/2L=3f1.
f1:f2:f3:f4:...=1:2:3:4:...
L=lambda1/2 or lambda 1=2L.
Its called as the fundamental node.
It has 2 and 3 anti nodes so,
lambda2= L.
The frequency
f2=v/lambda2=v/L=2×v/2L=2f1.
The frequency,
f3=v/lambda3=3v/2L=3f1.
f1:f2:f3:f4:...=1:2:3:4:...
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