Question

derivation of motion v2_u2=2as

Answer 1

hope it will help u

Answer 2

We know distance covered , s = area of trapezuim OABC

or s = ( BC + OA / 2 ) × AD

Now a = BD / AD

or AD = BD / a = BC - DC / a = v - u / a

Also BC = v ; OA = u

From equation ( 1 ) above , we have

s = ( v + u / 2 ) ( v - u )

or s = v² - u² / 2a

or v² - u² = 2as