Question

derivation of Newton's second law of motion​

Answer 1

Answer:

Newton's Second law of motion :- The rate of change of momentum is directly proportional to the force applied on the system. ... Here, K is the proportionality constant. It's value is 1 . Units of Force are given by the units of mass and acceleration.

Answer 2

DERIVATION BY NEWTON'S SECOND LOW...

$</p><p></p><p>If \: a \: body \: of \: mass \: m \: is \: moving \: with \: a \: velocity \: v, \: then \: it \: linear \: momentum \: is \: \\ p = mv \: \\ dfferentiating \: both \: side \: with \: respect \: to \: time \: t \: we \: get \: \\ \frac{dp}{dt} = \frac{d}{dt}(ma) \\ \: \: \: \: \: \: \: = \: m \frac{dv}{dt} \\ \: \: \: \: \: \: \: = ma \: \: \: \: \: \: \: (as \: \frac{dv}{dt} =a \: ) \\ here \: a \: is \: the \: acceleration \: of \: the \: body . \\ according \: to \: netwon \: second \: law \: \\ applied \: force \: \: \alpha \: \: rate \: of \: change \: in \: momentum. \\ f \: \: \alpha \: \frac{dp}{dt} \\ f \: \: \alpha \: ma \\ f \: \: = kma \: \: \: \: (k \: is \: a \: constant) \\ \\ if \: f = a = m = 1 \: \\ then \: k = 1 \\ </p><p>there \: for \: \\ f = ma$