Question

Derivation of potential due to an electric dipole at axis of dipole???​

Answer 1

derivation decoded dude

thank meh

Answer 2

Answer:

$\frac{KP}{x²-L²}$

Explanation:

Let us assume, P = q(2L)

$V_net$M = $V_1$ + $V_2$

= -$\frac{Kq}{x+L}$ + $\frac{Kq}{x+L}$

= Kq($\frac{1}{x-L}$ - $\frac{1}{x+L}$)

= Kq($\frac{x+L-x+L}{x²-L²}$)

= $\frac{Kq(2q)}{x²-L²}$

= $\frac{KP}{x²-L²}$