Question

derivation of relation between range and hmax​

Answer 1

Answer:

ANSWER

Maximum height, H =

2g

u

2

sin

2

θ

-----(i)

Horizontal range, R =

g

u

2

sin2θ

=

g

2u

2

sinθcosθ

------(ii)

Divide (i) by (ii), we get

R

H

=

4

tanθ

or tanθ=4H/R or θ=tan

−1

(4H/R)

Explanation:

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