Physics, asked by mgmastergamer8, 4 months ago

derivation of second equation of motion by calulation method​

Answers

Answered by abdurrahmankhan4
1

Answer:

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Answered by Anonymous
1

Answer:

Explanation:

Velocity is defined as the rate of change of displacement. This is mathematically represented as:

Velocity=Displacement/Time

Rearranging, we get

Displacement=Velocity×Time

If the velocity is not constant then in the above equation we can use average velocity in the place of velocity and rewrite the equation as follows:

Displacement=(Initial Velocity+Final Velocity)/2×Time

Substituting the above equations with the notations used in the derivation of the first equation of motion, we get

s=(u+v)/2×t

From the first equation of motion, we know that v = u + at. Putting this value of v in the above equation, we get

s=u+(u+at))/2×t

s=(2u+at)/2×t

s=(2u/2+at/2)×t

s=(u+1/2at)×t

On further simplification, the equation becomes:

s=ut+1/2at^2

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