Question

derivation of sin theta plus cos theta by root under of 1 plus sin 2 theta​

Answer 1

Answer:

sin theta plus cos theta ÷ root under of 1 plus sin 2 theta

sin theta plus cos theta ÷ root under of (sin theta plus cos theta) plus sin 2 theta

sin theta plus cos theta ÷ root under of (sin^2theta plus cos^2theta) plus 2* sin theta* cos theta

sin theta + cos theta ÷ root under of (sin theta + cos theta)^2

sin theta + cos theta ÷ (sin theta + cos theta)

= 1