Question

derivation of the 3 equations of motion

Answer 1

S=area of OABC

S=1/2 (V+u)*t

S+1/2(v+u)*v-u/a   (from 1st eq we will find the value of t)

S=v+u/2*v-u/a

S=v*v-u*u/2a

2as=v*v-u*u

v*v=u*U+2as

Answer 2

Answer:

your answer is in attached picture