Question

derivation of the equation s= 1/2(v+u)t by integration

Answer 1

As we know v=ds/dt. => ds= vdt =u+at)dt. So,when t=0,dis=0. Nd when t=t, dis= s now integrating within these limits,we get,. Integral ds =integral (u+at)dt => u integral dt +a Integral t dt => [s] =u[t] +a[t^2/2] =>s-0 = u(t-0) + a[t^2/2 -0]. => s = ut + 1/2 at^2