Physics, asked by riajani, 9 months ago

derivation of the formula F=m×a


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Answers

Answered by AdityaXbadvibesX
2

Answer:

let a force F be applied on a body of mass m for time t due to which it's velocity changes from u to v . then

Initial momentum of the body = mu

Final momentum of the body = mb

Change in momentum of the body in the second = mv- mu= m( v- u)

Rate of change of momentum = Change in momentum / time= m( v - u)/ t

But acceleration a = Change in velocity /time = v - u/ t

therefore , rate of change of momentum = ma

= mass × acceleration

Answered by anshikameena29
1

Answer:

Consider a body of mass m' moving with velocity v. Which is the required equation of force. ... If a body of mass "m" moving at initial velocity "u" accelerates uniformly with an acceleration "a" for time"t" so that it's final velocity changes Into "v.

Then initial momentum = P1 -P2

=mv - mu

= m(v - u )

According to 2nd law of motion

F = P2 - P1/time

F = ma (v - u ) / time

F = ma

Hence, proved

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