derivation of the formula F=m×a
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Answers
Answer:
let a force F be applied on a body of mass m for time t due to which it's velocity changes from u to v . then
Initial momentum of the body = mu
Final momentum of the body = mb
Change in momentum of the body in the second = mv- mu= m( v- u)
Rate of change of momentum = Change in momentum / time= m( v - u)/ t
But acceleration a = Change in velocity /time = v - u/ t
therefore , rate of change of momentum = ma
= mass × acceleration
Answer:
Consider a body of mass m' moving with velocity v. Which is the required equation of force. ... If a body of mass "m" moving at initial velocity "u" accelerates uniformly with an acceleration "a" for time"t" so that it's final velocity changes Into "v.
Then initial momentum = P1 -P2
=mv - mu
= m(v - u )
According to 2nd law of motion
F = P2 - P1/time
F = ma (v - u ) / time
F = ma
Hence, proved
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