derivation of the formula three successive discounts {50 points}
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Successive Discount : The formula for total discount in case of successive-discounts :
If the first discount is x% and 2nd discount is y% then ,
Total discount = ( x + y - xy / 100 ) %Example :
1) The successive-discount of 10% and 20% are given on the purchase of a bag . If the price of the bag is $ 2250, find the selling price.
Solution:
As the successive discount is 10% and 20%
Total discount = ( x + y - xy / 100 ) %
x = 10% and y = 20%
Total discount = [ 10 + 20 – ( 10 x 20) / 100] %
= ( 30 – 200 /100 ) %
Total discount = 28%
Discount = 28% of 2250
Discount = ( 28 / 100 ) x 2250
Discount = $630
S.P = M.P – Discount
= 2250 – 630
Selling price = $ 1620
If the first discount is x% and 2nd discount is y% then ,
Total discount = ( x + y - xy / 100 ) %Example :
1) The successive-discount of 10% and 20% are given on the purchase of a bag . If the price of the bag is $ 2250, find the selling price.
Solution:
As the successive discount is 10% and 20%
Total discount = ( x + y - xy / 100 ) %
x = 10% and y = 20%
Total discount = [ 10 + 20 – ( 10 x 20) / 100] %
= ( 30 – 200 /100 ) %
Total discount = 28%
Discount = 28% of 2250
Discount = ( 28 / 100 ) x 2250
Discount = $630
S.P = M.P – Discount
= 2250 – 630
Selling price = $ 1620
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Solution:
As the successive discount is 10% and 20%
Total discount = ( x + y - xy / 100 ) %
x = 10% and y = 20%
Total discount = [ 10 + 20 – ( 10 x 20) / 100] %
= ( 30 – 200 /100 ) %
Total discount = 28%
Discount = 28% of 2250
Discount = ( 28 / 100 ) x 2250
Discount = $630
S.P = M.P – Discount
= 2250 – 630
Selling price = $ 1620
As the successive discount is 10% and 20%
Total discount = ( x + y - xy / 100 ) %
x = 10% and y = 20%
Total discount = [ 10 + 20 – ( 10 x 20) / 100] %
= ( 30 – 200 /100 ) %
Total discount = 28%
Discount = 28% of 2250
Discount = ( 28 / 100 ) x 2250
Discount = $630
S.P = M.P – Discount
= 2250 – 630
Selling price = $ 1620
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